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Orthopaedic Surgery Board Exam Review: ABOS Part I & AAOS OITE Prep Questions | Part 22210

Orthopedic Biomechanics & Fracture Fixation Review for ABOS Part I & AAOS OITE | Part 22204

23 Apr 2026 86 min read 36 Views
Orthopaedic Surgery Board Review: Fracture Healing, Biomechanics & Internal Fixation MCQs | Part 21565

Key Takeaway

This module offers a comprehensive review of orthopedic biomechanics and fracture fixation principles, featuring 50 advanced multiple-choice questions. It covers intramedullary nails, plates, screws, external fixators, and various surgical techniques. Designed for ABOS Part I and AAOS OITE exam preparation, it deepens understanding of implant function, bone healing, and common orthopedic trauma scenarios.

Orthopedic Biomechanics & Fracture Fixation Review for ABOS Part I & AAOS OITE | Part 22204

Comprehensive 100-Question Exam


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Question 1

A 32-year-old male sustains a transverse mid-diaphyseal femoral fracture. He is treated with a reamed, statically locked intramedullary nail. Biomechanically, what is the primary advantage of this construct over a rigidly compressed plate for this specific fracture pattern?





Explanation

Correct Answer: C

Intramedullary (IM) nails are load-sharing devices, meaning they share axial, bending, and torsional loads with the bone. This central placement along the mechanical axis minimizes bending moments and allows for controlled micromotion at the fracture site, which is a potent stimulus for secondary bone healing via callus formation (endochondral ossification). A rigidly compressed plate, conversely, aims for absolute stability and primary bone healing (direct cortical healing). While IM nailing often involves less soft tissue dissection, which is a surgical advantage, the primary biomechanical benefit in terms of healing mechanism is load sharing and relative stability. Stress shielding is reduced compared to rigid plates but not eliminated. Ultimate tensile strength is a material property, not a construct advantage over a plate.

Question 2

A 48-year-old female with a comminuted tibial shaft fracture is undergoing intramedullary nailing. The surgeon opts for a reamed technique. What is the most significant biomechanical consequence of reaming the medullary canal in this scenario?





Explanation

Correct Answer: B

Reaming the medullary canal allows for the insertion of a larger diameter intramedullary nail. The bending and torsional stiffness of a nail are highly dependent on its diameter and cross-sectional geometry (specifically, the area moment of inertia). A larger diameter nail provides a tighter fit within the canal, maximizing bone-implant contact and significantly increasing the overall stiffness of the construct. This enhanced stiffness is crucial for stabilizing comminuted fractures, where the bone itself provides little inherent stability. Reaming temporarily disrupts the endosteal blood supply and can cause thermal osteonecrosis if not performed carefully, thus option A and C are incorrect. IM nails remain load-sharing devices, not load-bearing, and reaming does not directly facilitate dynamic compression (which is achieved by specific locking screw configurations).

Question 3

A 28-year-old male sustains a spiral mid-shaft humeral fracture. Antegrade intramedullary nailing is performed. To achieve optimal rotational stability in this fracture pattern, which biomechanical feature of the construct is most critical?





Explanation

Correct Answer: C

In spiral or comminuted fractures, the bone fragments themselves cannot resist rotational forces due to the lack of inherent bony stability. Therefore, rotational stability is primarily achieved by the interlocking screws. These screws connect the intramedullary nail to both the main proximal and distal bone fragments, effectively linking them and preventing independent rotation between the implant and the bone. While nail diameter, material properties, and a tight fit contribute to overall construct stiffness, interlocking screws are the direct and most critical mechanism for resisting rotation in unstable fracture patterns. Pre-bending helps with anatomical alignment but does not directly provide rotational stability to the fracture fragments.

Question 4

A 55-year-old patient with a comminuted distal tibia fracture is treated with a supramalleolar intramedullary nail. The surgeon places two proximal and two distal interlocking screws. If the surgeon were to remove one proximal and one distal screw (converting to a single screw at each end), what would be the primary biomechanical consequence?





Explanation

Correct Answer: C

The 'working length' of an intramedullary nail construct is defined as the distance between the most proximal and most distal interlocking screws. Increasing this distance (by removing screws or placing them further apart) results in a longer working length. Biomechanically, a longer working length leads to a less stiff construct, allowing for increased controlled micromotion at the fracture site. This controlled micromotion can be beneficial for stimulating callus formation (secondary bone healing) but can also risk excessive motion and delayed union if the working length is too long for the fracture pattern. Conversely, a shorter working length (more screws, closer together) increases stiffness. Removing screws would decrease, not increase, resistance to screw pullout and would not convert to absolute stability.

Question 5

A 70-year-old female with osteopenia sustains a mid-shaft femoral fracture. An IM nail is inserted, but intraoperative imaging reveals the distal tip of the nail terminates approximately 5 cm proximal to the metaphyseal flare. What is the most significant biomechanical concern with this nail length?





Explanation

Correct Answer: C

A too-short intramedullary nail, especially one that terminates within the diaphysis rather than extending into the metaphysis, creates a stress riser at its tip. Biomechanically, this point becomes a site of concentrated stress where the stiff implant abruptly ends, transferring load to the adjacent bone. This significantly increases the risk of a periprosthetic fracture originating at or just beyond the nail tip, particularly in osteopenic bone where bone quality is already compromised. Optimal nail length involves extending into the metaphysis to distribute stress over a larger area and avoid these stress risers. Impingement on the knee joint would occur if the nail was too long and protruded distally. Rotational stability is primarily provided by interlocking screws, and dynamic compression is a function of screw configuration, not nail length.

Question 6

A surgeon is choosing an intramedullary nail for a young, active patient with a tibia fracture. They are considering two options: one made of stainless steel and another of titanium alloy. From a biomechanical perspective, which material property is most relevant to minimizing long-term stress shielding of the bone?





Explanation

Correct Answer: D

Young's Modulus (or modulus of elasticity) is a measure of a material's stiffness or resistance to elastic deformation under stress. Cortical bone has a Young's Modulus of approximately 17-20 GPa. Stainless steel has a Young's Modulus of around 200 GPa, while titanium alloys are closer at approximately 110 GPa. The greater the mismatch in stiffness between the implant and the bone, the more the implant will bear the physiological load, leading to stress shielding of the adjacent bone. Therefore, a lower Young's Modulus (like that of titanium) is biomechanically advantageous for reducing stress shielding, allowing the bone to experience more physiological stress and promoting its natural remodeling and healing processes. Other properties like tensile strength, hardness, corrosion resistance, and fatigue limit are important for implant integrity but are not the primary drivers of stress shielding.

Question 7

A 60-year-old male with a subtrochanteric femoral fracture is undergoing antegrade IM nailing. The surgeon is carefully selecting the entry portal. What is the primary biomechanical rationale for ensuring the entry portal is appropriately positioned, typically at the tip of the greater trochanter or slightly medial to it?





Explanation

Correct Answer: C

An optimal entry portal for antegrade femoral nailing is crucial for proper nail alignment and to prevent iatrogenic complications. If the entry point is too medial (e.g., piriformis fossa entry with a lateral approach) or too far lateral, it can lead to eccentric reaming of the greater trochanter or piriformis fossa. This can potentially cause iatrogenic comminution or fracture, especially in subtrochanteric fractures where the bone is already compromised. A correctly placed entry portal ensures the nail follows the natural curvature of the femur, is well-centered in the medullary canal, and minimizes stress risers, thereby ensuring optimal nail trajectory and reducing the risk of malalignment. While avoiding neurovascular injury (like the superior gluteal artery) is important, the primary biomechanical rationale for the position of the entry portal relates to bone integrity and nail trajectory.

Question 8

A 35-year-old male presents with a segmental femoral shaft fracture, with a 6 cm intervening fragment. He is treated with a reamed, statically locked IM nail. Biomechanically, what is the most significant challenge posed by this fracture pattern to the IM nail construct?





Explanation

Correct Answer: D

In a segmental fracture, the intervening fragment effectively creates two separate fracture sites, meaning the intramedullary nail must bridge a longer span without direct bony support between the two main fragments. This significantly increases the bending and torsional moments acting on the implant, as the nail must bear a greater proportion of the physiological load across this unsupported segment. This increased loading can lead to a higher risk of implant fatigue failure, delayed union, or nonunion if the construct is not sufficiently robust. The intervening fragment does not act as a stress shield; rather, it creates a zone of instability that the nail must bridge. The need for interlocking screws is often increased, not reduced, in such unstable patterns.

Question 9

A 40-year-old patient with a transverse mid-diaphyseal tibia fracture is initially treated with a statically locked IM nail. After 8 weeks, there is evidence of delayed union. The surgeon decides to dynamize the nail by removing one of the distal interlocking screws. What is the primary biomechanical objective of this intervention?





Explanation

Correct Answer: C

Dynamization, typically achieved by removing one or more interlocking screws (often from one end of the nail), converts a statically locked construct into a dynamically locked one. Biomechanically, this allows for controlled axial micromotion (telescoping) and compression at the fracture site. This axial shortening and micromotion are potent stimuli for secondary bone healing and callus formation (Wolff's Law), which can be beneficial in cases of delayed union, especially in transverse or short oblique fractures where some cortical contact exists. It does not increase rotational stability (it often reduces it), convert the nail to a load-bearing device, or eliminate all motion; rather, it specifically allows for controlled motion.

Question 10

During antegrade intramedullary nailing of a tibial shaft fracture, the surgeon encounters difficulty advancing the nail past the mid-diaphysis, with the nail tip impinging on the anterior cortex. What is the most likely biomechanical reason for this difficulty?





Explanation

Correct Answer: B

The tibia naturally exhibits an anterior apex recurvatum (anterior bow) in the sagittal plane. Intramedullary nails designed for the tibia are manufactured with an anterior apex bow to match this physiological curvature. If a nail with an incorrect sagittal curvature (e.g., a posterior apex bow or a nail that is too straight) is used, or if the nail's curvature is not properly aligned with the bone's, it can impinge on the anterior or posterior cortex during insertion, making advancement difficult and potentially leading to malalignment (procurvatum or recurvatum). While an anterior entry portal can also cause anterior cortical impingement, the scenario described (nail tip impinging on the anterior cortex) is most characteristic of a nail with a posterior apex bow trying to navigate an anteriorly bowed canal.

Question 11

Which statement best describes the primary biomechanical function of a lag screw?





Explanation

Correct Answer: B

The lag screw principle is fundamental to fracture fixation. It works by converting the rotational torque of screw insertion into axial compression across a fracture. This is achieved by having the screw threads engage only the far cortex (or the fragment to be compressed), while the screw shaft glides freely through a larger pilot hole (glide hole) in the near cortex (or the fragment through which compression is desired). This differential engagement pulls the fragments together, generating interfragmentary compression. Absolute stability (Option A) is the goal of lag screw fixation, but the 'how' is through compression. Neutralization (Option C) and buttress (Option E) are functions of plates, not the primary function of a lag screw itself. Fixation of osteochondral fragments (Option D) can be done with lag screws, but the 'non-compressive' part is incorrect if referring to a true lag screw.

Question 12

A 4.5 mm cortical screw is primarily designed with which thread characteristic compared to a 6.5 mm cancellous screw?





Explanation

Correct Answer: C

Cortical screws are designed for dense cortical bone. To maximize purchase in this environment, they have a finer thread pitch (more threads per unit length) and a shallower thread depth. This increases the number of points of contact within the dense bone. Cancellous screws, conversely, are designed for softer cancellous bone, thus having a coarser thread pitch and a larger thread depth to provide greater purchase in less dense bone. Outer diameter and core diameter (Option A) are specific measurements, but the thread morphology is the primary distinguishing feature. Self-tapping tips (Option D) are a feature, not a primary distinguishing characteristic between all cortical vs. cancellous screws. Flute design (Option E) is relevant for self-tapping or self-drilling screws, but not the fundamental difference in thread morphology.

Question 13

When inserting a standard 3.5 mm cortical screw into the femoral shaft, what is the appropriate drill bit size for the pilot hole if tapping is to be performed?





Explanation

Correct Answer: C

For a standard 3.5 mm cortical screw, the outer (thread) diameter is 3.5 mm and the inner (core) diameter is typically 2.7 mm. When tapping is performed, the pilot hole should match the core diameter of the screw to ensure that the threads cut by the tap, and subsequently the screw, achieve maximum purchase. A 2.5 mm drill bit (Option B) is used for a 3.5 mm non-locking screw through a plate for creating compression (dynamic compression plate hole). A 2.0 mm (Option A) is for 2.7 mm screws. A 3.2 mm (Option D) is typically for larger screws like 4.5 mm cortical screws (where the core diameter is 3.2 mm). A 3.5 mm (Option E) would prevent any thread purchase.

Question 14

What is the primary biomechanical advantage of a locking screw construct compared to a conventional screw-plate construct in osteoporotic bone?





Explanation

Correct Answer: C

Locking screws thread into the plate, creating a fixed-angle construct. This effectively turns the screw-plate interface into a 'beam' rather than relying on friction between the plate and bone for stability. This angular stability is highly resistant to screw pull-out, which is a significant problem in osteoporotic bone where screw purchase is poor. While some compression can be achieved with locking plates (e.g., with specific techniques or combi-holes), their primary biomechanical advantage over conventional constructs, especially in poor bone, is angular stability and improved pull-out resistance (Option C). They generally reduce interfragmentary compression (Option A) compared to traditional lag screws. Locking plates tend to be stiffer and can increase stress shielding (Option B). They provide rigid fixation, which reduces micromotion (Option D), though some controlled micromotion can be beneficial for callus formation. Lag compression (Option E) is a function of a lag screw, and while locking screws can be used in a lag fashion through combi-holes, it's not their primary distinguishing advantage.

Question 15

Cannulated screws are particularly advantageous in which of the following scenarios?





Explanation

Correct Answer: B

Cannulated screws have a hollow core, allowing them to be inserted over a guide wire. This feature is extremely useful for precise placement, especially in articular fractures, epiphyseal/metaphyseal fractures, or percutaneous applications where accurate trajectory and minimal soft tissue disruption are desired. Examples include femoral neck fractures, scaphoid fractures, or malleolar fractures. Diaphyseal fractures (Option A) typically use solid screws for torsional rigidity. Maximal cortical purchase (Option C) is achieved with solid screws matching the core diameter for the pilot hole. While they can create compression (Option D), their cannulation isn't for maximal compression. Comminuted metaphyseal fractures (Option E) might use locking plates, not primarily cannulated screws for their cannulation feature alone.

Question 16

What is the main difference between a self-tapping screw and a conventional tapping screw in terms of surgical technique?





Explanation

Correct Answer: B

A conventional (non-self-tapping) screw requires that a pilot hole be drilled and then a tap (a separate instrument that cuts threads into the bone) be used before the screw is inserted. A self-tapping screw has cutting flutes at its tip that create the threads in the bone as the screw is inserted, eliminating the need for a separate tapping step. This simplifies the surgical procedure. Self-tapping screws don't always require a larger pilot hole (Option A); the pilot hole size is related to the screw's core diameter. Self-tapping screws are used in both cortical and cancellous bone (Option C). Conventional tapping screws generally provide more pull-out strength (Option D) because the threads are pre-cut, leading to better bone-screw interface, though self-tapping screws have improved significantly. Both types of screws have sharp tips (Option E), but self-tapping screws have flutes for cutting.

Question 17

In the context of plate and screw fixation, what is the primary role of a neutralization plate?





Explanation

Correct Answer: B

A neutralization plate is used in conjunction with interfragmentary lag screws. The lag screws provide the primary interfragmentary compression (absolute stability), while the neutralization plate's role is to 'neutralize' or protect these lag screws from shared forces (bending, shear, torsion) that could lead to failure of the lag screw fixation or loss of compression. It shares the load with the lag screws, but the lag screws are doing the initial compression. Direct compression (Option A) is the role of the lag screw or a DCP. Primary load-bearing in comminuted fractures (Option C) is a bridging plate function. Bridging (Option D) is also a separate plate function for comminuted fractures/defects. Buttress (Option E) plates prevent collapse, usually in metaphyseal or articular areas.

Question 18

Overtightening a screw during fracture fixation, particularly in diaphyseal bone, can lead to which of the following complications?





Explanation

Correct Answer: C

Overtightening a screw generates excessive torque, which can lead to several problems: 1) Stripping the bone threads, resulting in loss of purchase. 2) Creation of microfractures in the bone around the screw, weakening its fixation. 3) Generation of heat and excessive localized pressure leading to pressure necrosis of the bone around the screw, which can then lead to aseptic loosening or even infection if bacteria gain access. While initial compression is desired (Option A), overtightening goes beyond the elastic limits of the bone. Stress shielding (Option B) is unrelated. Blood supply (Option D) is not improved, and excessive pressure can compromise it. Premature degradation (Option E) of bioabsorbable implants is not a direct consequence of overtightening itself, but rather related to their material properties and environment.

Question 19

How does the design of a Dynamic Compression Plate (DCP) facilitate interfragmentary compression?





Explanation

Correct Answer: B

The Dynamic Compression Plate (DCP) utilizes a specific hole design that is shaped like an inclined cylinder. When a screw is inserted through an eccentrically drilled pilot hole (i.e., drilled at one end of the oval hole), the spherical screw head contacts the inclined plane and slides down it as it is tightened. This translation of the screw head along the inclined plane pulls the bone fragment toward the plate, generating axial compression across the fracture site. Variable angle locking screws (Option A) are for locking plates, not DCPs. Internal spring mechanisms (Option C) are not part of DCP design. Self-tapping screws (Option D) simplify insertion but don't provide the compression mechanism. Pre-bending (Option E) helps prevent gapping on the far cortex but is not the primary mechanism of interfragmentary compression using the plate holes.

Question 20

A surgeon is fixing a pediatric forearm fracture and wants to minimize the need for future hardware removal. Which screw material would be most appropriate, considering biocompatibility and biomechanics?





Explanation

Correct Answer: D

Bioabsorbable polymers like Poly-L-lactic acid (PLLA) or polylactide-co-glycolide (PLGA) are specifically designed to degrade over time, eliminating the need for a second surgery for hardware removal. This is particularly advantageous in pediatric fractures where bone remodeling is significant and future growth is a concern. While stainless steel (Option A) and titanium (Option C) are highly biocompatible, they are permanent implants requiring removal if they cause symptoms or interfere with growth. Cobalt-chrome (Option B) is strong but generally used for bearing surfaces in joint replacements. Nitinol (Option E) is a shape-memory alloy used in specific applications like staples or small implants, but less commonly for primary fracture fixation screws meant to absorb.

Question 21

A 78-year-old female with severe osteoporosis sustains a highly comminuted distal femur fracture (AO/OTA 33-C3) after a low-energy fall. You decide to proceed with open reduction and internal fixation using a locking plate. What is the primary biomechanical rationale for choosing a locking plate over a conventional Dynamic Compression Plate (DCP) in this specific patient and fracture pattern?





Explanation

Correct Answer: C

The primary biomechanical advantage of a locking plate in a highly comminuted fracture, especially in osteoporotic bone, is its ability to create a fixed-angle construct. The threaded screw heads lock into the plate, forming a rigid unit that functions as an 'internal fixator' or 'extramedullary splint.' This construct provides stability that is largely independent of plate-bone friction or compression, which is severely compromised in osteoporotic bone where screw pull-out strength is poor and cortical contact is minimal due to comminution. This allows for stable fixation even with poor bone quality.

  • Option A is incorrect: Interfragmentary compression is not the primary goal or mechanism in highly comminuted fractures, where relative stability and indirect healing are preferred. Locking plates primarily bridge comminution rather than compress it.
  • Option B is incorrect: While titanium locking plates have a lower modulus of elasticity than stainless steel, the fixed-angle construct itself is generally quite rigid and can lead to stress shielding, not reduce it. The material choice influences modulus, but the construct's rigidity is the dominant factor for stress shielding.
  • Option D is incorrect: While locking plates provide robust stability, 'absolute stability' (no micromotion) is not always achievable or desirable in comminuted fractures, where controlled micromotion promotes secondary bone healing. Early full weight-bearing depends on many factors, not solely the plate type.
  • Option E is incorrect: Locking plates are generally less malleable than conventional plates, and excessive bending can damage the threaded screw holes. Anatomically pre-contoured locking plates exist, but the material itself is not inherently more malleable.

Question 22

A 35-year-old male sustains a simple transverse midshaft tibial fracture. You plan to fix this with a conventional Dynamic Compression Plate (DCP) to achieve absolute stability. When contouring the plate, what is the primary purpose of 'pre-bending' the plate slightly away from the bone at the fracture site?





Explanation

Correct Answer: C

Pre-bending a conventional plate, particularly for transverse or short oblique fractures, is a critical technique to achieve effective interfragmentary compression across the entire fracture plane. When the plate is slightly pre-bent away from the bone at the fracture site, tightening the screws on either side pulls the plate flat against the bone. This action drives the fracture fragments together, creating compression on both the near and, crucially, the far (trans) cortex. Without pre-bending, tightening the screws would primarily compress the near cortex, potentially causing the far cortex to gap open, leading to an unstable construct and impaired healing.

  • Option A is incorrect: Pre-bending is done to enhance compression and absolute stability, which increases stiffness, not reduces it.
  • Option B is incorrect: Screw purchase is primarily determined by screw length, diameter, and bone quality, not plate pre-bending.
  • Option D is incorrect: Pre-bending is a technique for open plating to achieve compression, not specifically for MIPO.
  • Option E is incorrect: Pre-bending is about achieving compression, not directly reducing stress shielding. Rigid compression constructs can still cause stress shielding.

Question 23

A 42-year-old patient requires internal fixation for a long bone fracture. The surgeon is debating between a 316L stainless steel plate and a Ti-6Al-4V titanium alloy plate. From a long-term biological and biomechanical perspective, what is a distinct advantage of the titanium alloy plate?





Explanation

Correct Answer: C

Titanium alloys (e.g., Ti-6Al-4V) have a modulus of elasticity that is closer to that of cortical bone compared to 316L stainless steel. This property makes titanium more 'bone-friendly' as it more closely matches the elastic modulus of bone. This congruence can help reduce the magnitude of stress shielding, a phenomenon where the implant bears too much load, leading to disuse osteopenia in the underlying bone. While both materials are strong, the elastic modulus difference is a key biomechanical advantage for titanium in terms of long-term bone health.

  • Option A is incorrect: Stainless steel is generally more radio-opaque than titanium, making titanium implants sometimes harder to visualize clearly on plain radiographs.
  • Option B is incorrect: While modern titanium alloys have excellent fatigue resistance, 316L stainless steel also has very good fatigue properties. The statement 'superior fatigue resistance' is not a universally distinct advantage of titanium over stainless steel in all forms.
  • Option D is incorrect: This statement is true (stainless steel is more prone to corrosion and ion release), but it describes a disadvantage of stainless steel, not an advantage of titanium. The question asks for a distinct advantage of titanium.
  • Option E is incorrect: Titanium alloys are generally more expensive and more challenging to manufacture than stainless steel, making this statement incorrect.

Question 24

A 28-year-old male sustains a long oblique fracture of the midshaft humerus. After achieving interfragmentary compression with two lag screws, a plate is applied to the lateral aspect of the humerus. What is the primary biomechanical role of this plate in this specific construct?





Explanation

Correct Answer: D

When lag screws are used to achieve interfragmentary compression in an oblique or spiral fracture, they provide absolute stability against shear forces. However, lag screws alone are weak against bending and torsional forces. A 'neutralization plate' is applied over the lag screws to protect them from these bending, torsional, and shear stresses that would otherwise cause the lag screws to fail or the fracture to displace. The plate 'neutralizes' these forces, allowing the lag screws to maintain their interfragmentary compression and promote primary bone healing.

  • Option A is incorrect: The lag screws already provide the primary interfragmentary compression. The plate's role is not to add more compression but to protect the existing compression.
  • Option B is incorrect: Buttress plates are typically used in metaphyseal or articular fractures to prevent axial collapse or displacement of fragments, not for diaphyseal oblique fractures fixed with lag screws.
  • Option C is incorrect: Bridging plates are used for comminuted fractures where anatomical reduction and compression are not feasible, promoting relative stability. This scenario describes absolute stability with lag screws.
  • Option E is incorrect: Tension band principles convert tensile forces into compression and are used for specific eccentric loading fractures (e.g., olecranon), not for protecting lag screws.

Question 25

A 55-year-old male sustains a highly comminuted segmental fracture of the midshaft femur. You opt for open reduction and internal fixation with a bridging locking plate. To optimize secondary bone healing via callus formation, what is the most appropriate strategy regarding the 'working length' of the plate construct?





Explanation

Correct Answer: C

For highly comminuted fractures treated with bridging osteosynthesis (e.g., a bridging locking plate), the goal is relative stability to promote secondary bone healing through callus formation. The 'working length' of the plate construct is the segment of the plate that spans the comminuted zone and is not rigidly fixed to bone. A longer working length (achieved by placing fewer screws and spreading them further apart in the main proximal and distal fragments) reduces the stiffness of the construct. This allows for controlled, limited micromotion at the fracture site, which is a potent stimulus for callus formation and secondary bone healing. Conversely, a short working length creates a very stiff construct, which can inhibit callus formation and potentially lead to stress shielding or fatigue failure of the implant if the bone does not heal quickly.

  • Option A and B are incorrect: Maximizing screws close to the fracture creates a short working length and a very stiff construct, which is detrimental to secondary healing.
  • Option D is incorrect: While bicortical screw purchase is generally desirable for strength, the distribution of screws to achieve an optimal working length is more critical for promoting secondary healing in this context.
  • Option E is incorrect: Working length is a crucial biomechanical principle for all plate constructs, especially bridging plates, and significantly influences the mode of healing.

Question 26

A 62-year-old female undergoes open reduction and internal fixation of a distal radius fracture with a volar locking plate. Six months postoperatively, she develops progressive pain and weakness with thumb extension, eventually leading to an Extensor Pollicis Longus (EPL) rupture. What is the most likely cause of this complication?





Explanation

Correct Answer: D

Penetration of the dorsal cortex by excessively long screws is a well-known and critical complication of volar distal radius plating. The Extensor Pollicis Longus (EPL) tendon, along with other extensor tendons, lies in close proximity to the dorsal cortex. Even slight screw prominence can cause chronic irritation, attrition, and eventual rupture of these tendons, particularly the EPL due to its course around Lister's tubercle. Careful measurement of screw length and intraoperative fluoroscopic verification in multiple planes are essential to prevent this.

  • Option A is incorrect: While over-tightening can damage plate threads, it's not a direct cause of EPL rupture.
  • Option B is incorrect: Inadequate screws would lead to construct instability and fracture displacement, not typically isolated EPL rupture.
  • Option C is incorrect: Improper plate contouring can cause flexor tendon irritation if the plate is too prominent volarly, but EPL rupture is a dorsal complication.
  • Option E is incorrect: Median nerve injury is a risk during the volar approach, but it would present with sensory and motor deficits in the median nerve distribution, not isolated EPL rupture.

Question 27

A 40-year-old male presents with a Gustilo-Anderson Type IIIA open fracture of the midshaft tibia. He has significant soft tissue loss and contamination. While considering definitive fixation, which of the following is a relative contraindication for immediate minimally invasive plate osteosynthesis (MIPO) in this scenario?





Explanation

Correct Answer: C

Minimally invasive plate osteosynthesis (MIPO) is designed to preserve soft tissue and periosteal blood supply, which is beneficial for fracture healing. However, in an open fracture with significant soft tissue stripping and contamination (Gustilo-Anderson Type IIIA), direct visualization of the fracture site is often critical for thorough debridement, irrigation, and assessment of fracture geometry and contamination. Attempting MIPO in such a compromised environment might hinder adequate debridement, increase the risk of infection, and potentially worsen the soft tissue envelope. In these cases, initial external fixation followed by delayed definitive fixation (which might still be plating, but after soft tissue healing) is often preferred.

  • Option A is incorrect: Simple transverse fractures are often well-suited for MIPO.
  • Option B is incorrect: MIPO can be part of rapid stabilization, but not if it compromises debridement in an open fracture.
  • Option D is incorrect: MIPO is often used for bridging comminuted fractures, where a long working length is desirable.
  • Option E is incorrect: Distal tibia fractures are commonly treated with MIPO techniques.

Question 28

A 50-year-old female sustains a transverse fracture of the olecranon. You decide to fix this using a tension band construct. What is the fundamental biomechanical principle underlying the use of a tension band in this specific fracture?





Explanation

Correct Answer: B

The tension band principle is most effectively applied to eccentric loading fractures where one side is under tension and the other under compression during physiological loading. The olecranon is a classic example: during elbow flexion, the triceps pulls on the olecranon, creating tensile forces on its posterior (subcutaneous) surface. A tension band construct (typically K-wires and a figure-of-eight wire, or sometimes a small plate) is placed on this tension side. As the elbow flexes, the tension band converts these tensile forces into compressive forces across the fracture site, thus stabilizing the fracture and promoting healing.

  • Option A is incorrect: While it provides stability, the primary mechanism is force conversion, not simply eliminating all micromotion, which is often the goal of absolute stability with lag screws or DCPs.
  • Option C is incorrect: Bridging is for comminuted fractures where anatomical reduction is not possible or desired. The olecranon fracture is typically reduced anatomically.
  • Option D is incorrect: Buttressing is for articular fractures to prevent collapse under axial load, not the primary mechanism for an olecranon tension band.
  • Option E is incorrect: While it contributes to overall stability, the primary principle is the conversion of tensile forces, not solely neutralizing torsion.

Question 29

A 6-year-old child undergoes plate fixation for a distal femoral fracture. The plate crosses the distal femoral physis. The fracture heals uneventfully. What is the most significant long-term concern unique to this pediatric patient that would necessitate consideration for hardware removal?





Explanation

Correct Answer: D

In pediatric patients, the presence of open growth plates (physes) introduces a unique and critical consideration for internal fixation. A plate crossing or impinging upon a physis can cause damage to the growth plate, leading to premature physeal closure (growth arrest) or asymmetric growth, resulting in limb length discrepancy or angular deformity. Therefore, in children, plates near or across a physis are often removed once the fracture has healed to prevent or mitigate these growth disturbances. While other complications like infection, stress shielding, and hardware prominence can occur in both children and adults, physeal arrest is a concern unique to the growing skeleton.

  • Option A is incorrect: Infection is a risk for any implant in any age group.
  • Option B is incorrect: Stress shielding can occur, but physeal arrest is a more immediate and specific concern for children with plates crossing growth plates.
  • Option C is incorrect: Hardware prominence is a common issue in both adults and children, but physeal arrest is a more severe and unique pediatric complication.
  • Option E is incorrect: Imaging artifact is a general concern with metallic implants, not unique to children or the primary reason for removal.

Question 30

A 30-year-old male sustains a simple transverse midshaft femoral fracture. The surgeon decides to treat this with an intramedullary (IM) nail. If plate fixation were considered as an alternative, what is the primary biomechanical advantage of an IM nail over a plate for this specific diaphyseal fracture?





Explanation

Correct Answer: C

For diaphyseal fractures, intramedullary nails are biomechanically superior to plates primarily because they provide central load-sharing. The nail is placed within the medullary canal, close to the neutral axis of the bone. This allows the nail to share the physiological load with the bone more efficiently, reducing the eccentric loading seen with plates (which are external to the bone). This central load-sharing can lead to less stress shielding and more physiological loading of the healing bone. While soft tissue preservation (Option D) is also an advantage of nailing, the central load-sharing is the fundamental biomechanical superiority for diaphyseal fractures.

  • Option A is incorrect: IM nails typically provide relative stability, allowing for controlled micromotion and promoting secondary bone healing. Absolute stability is not their primary mechanism.
  • Option B is incorrect: While IM nails are very strong, their stiffness relative to plates depends on many factors (nail diameter, plate size, working length). The primary advantage is how they bear load, not necessarily always being stiffer in absolute terms.
  • Option D is incorrect: While IM nailing often involves less soft tissue stripping than traditional open plating, this is a surgical technique advantage, not a fundamental biomechanical one.
  • Option E is incorrect: IM nails typically promote secondary bone healing. Plates can achieve either primary (with absolute stability) or secondary (with relative stability/bridging) healing, depending on the construct.

Question 31

A 55-year-old male presents with a displaced intra-articular calcaneal fracture. You plan for open reduction and internal fixation. Which screw characteristic is most crucial for achieving interfragmentary compression across the fracture fragments?





Explanation

Correct Answer: B

Interfragmentary compression, the hallmark of lag screw technique, is achieved when the screw threads purchase only in the far fragment, while the near fragment is allowed to 'lag' or slide along the smooth, unthreaded portion of the screw shaft. This requires a partially threaded screw and a gliding hole in the near cortex, which must be larger than the major (thread) diameter of the screw, allowing the screw head to draw the near fragment towards the far fragment as it tightens. A fully threaded screw, without a gliding hole, would fix both fragments equally and not generate compression.

Question 32

In the context of fracture fixation, what is the primary biomechanical advantage of using a locking screw in a locking plate system compared to a non-locking cortical screw?





Explanation

Correct Answer: B

Locking screws thread into the plate, creating a fixed-angle construct. This effectively turns the screw-plate interface into a 'fixed-angle internal fixator', where the strength of the construct is not dependent on screw purchase into the near cortex, but rather on the angular stability created by the locked threads. This provides significantly improved pullout strength, especially beneficial in osteoporotic bone where traditional screw purchase is compromised. While reduced need for precise contouring is an advantage, the primary biomechanical benefit is the enhanced stability and pullout resistance due to the fixed-angle construct, rather than direct interfragmentary compression (which locking screws often limit).

Question 33

A surgeon is fixing a comminuted humeral shaft fracture with a neutralization plate. What is the primary role of the screws when used in a neutralization plate construct?





Explanation

Correct Answer: C

A neutralization plate is used to protect a primary lag screw or screws providing interfragmentary compression. Its main function is to shield the fracture from bending, torsional, and shear forces, allowing the lag screws to maintain compression without being subjected to disruptive stresses. The plate itself bears the majority of the external loads applied to the bone, thus 'neutralizing' these forces from reaching the fracture site. The screws fix the plate to the bone, but their primary biomechanical role in this construct is to hold the plate securely to provide the shielding effect, not to generate compression or share axial load equally in the immediate fracture zone.

Question 34

You are performing an arthrodesis of the subtalar joint. Which type of screw is typically preferred for maximizing compression across the joint surfaces and why?





Explanation

Correct Answer: B

For arthrodesis, maximizing compression across the fusion surfaces is paramount to promote fusion. Partially threaded cancellous screws are ideal for lag screw fixation in cancellous bone (like the tarsals) because their coarse threads provide excellent purchase in softer bone, and the unthreaded shaft allows the near fragment to slide, generating robust interfragmentary compression as the screw is tightened. This direct application of the lag screw principle is highly effective for achieving sustained compression across joint surfaces in an arthrodesis setting. While fully threaded cortical screws can be used in a lag fashion with proper overdrilling, partially threaded cancellous screws are specifically designed for this purpose in metaphyseal/epiphyseal bone.

Question 35

Regarding screw design, what distinguishes a cancellous screw from a cortical screw in terms of thread characteristics and typical application?





Explanation

Correct Answer: D

Cancellous screws are designed for optimal purchase in soft, cancellous bone. They typically have a larger core diameter relative to their outer thread diameter, and a coarser thread pitch, meaning fewer threads per unit length. This design maximizes the bone-screw interface in porous bone. Cortical screws are designed for dense cortical bone, featuring a smaller core diameter relative to thread diameter, and a finer thread pitch (more threads per unit length). This allows them to cut effectively into hard bone and provide strong purchase. Therefore, option D correctly describes cortical screws, and option B describes cancellous screws. The key distinction is finer pitch for cortical and coarser pitch for cancellous.

Question 36

A surgeon is performing an anterior cruciate ligament (ACL) reconstruction using a soft tissue graft. Which type of screw is most commonly used for femoral or tibial fixation of the graft and why?





Explanation

Correct Answer: C

Bioabsorbable interference screws are the most common choice for ACL graft fixation (both femoral and tibial tunnels) when using a soft tissue graft. They provide excellent interference fit and rigid primary fixation, compressing the graft against the tunnel wall. The advantage of bioabsorbability is that it avoids a permanent implant, which can be beneficial in case of revision surgery or future imaging. While other screw types could theoretically be used, interference screws are specifically designed for this application to achieve strong primary fixation and are often made from bioabsorbable materials like PLLA, PLDLA, or TCP composites.

Question 37

What is the primary function of a position screw in fracture fixation?





Explanation

Correct Answer: B

A position screw is used to hold two bone fragments together in a fixed position without actively compressing them. Unlike a lag screw, which specifically generates interfragmentary compression by threading only the far cortex (or having a gliding hole in the near cortex), a position screw threads into both the near and far cortices, or into both fragments, thus holding them at a fixed distance from each other. This is often used in syndesmotic fixation (e.g., tibiofibular syndesmosis) where excessive compression could lead to cartilage damage or loss of motion.

Question 38

Which of the following scenarios is most appropriate for the use of a fully threaded cortical screw in a lag fashion?





Explanation

Correct Answer: C

A fully threaded cortical screw can be used in a lag fashion to achieve interfragmentary compression. To do this, a gliding hole (larger than the major diameter of the screw) must be drilled in the near cortex, and a smaller thread hole (matching the core diameter) drilled and tapped in the far cortex. This technique is commonly used for oblique or spiral diaphyseal fractures where strong compression is desired. For example, a spiral tibial fracture often benefits from lag screw fixation across the fracture line. Syndesmotic injuries typically use position screws, locking plates are often used for comminuted fractures, and specific headless or cannulated screws are preferred for malleolar or tendon anchor fixation.

Question 39

What is the consequence of 'overtapping' a screw hole in cortical bone?





Explanation

Correct Answer: C

Overtapping refers to cutting threads that are too deep or too wide for the chosen screw. This effectively reduces the amount of bone in contact with the screw threads, diminishing the screw's purchase in the bone. The result is a weaker screw-bone interface, leading to reduced pullout strength and an increased risk of screw loosening. Proper tapping ensures an optimal fit between the screw threads and the bone, maximizing stability.

Question 40

A surgeon is considering the use of headless compression screws for a scaphoid fracture fixation. What is the primary advantage of a headless design in this application?





Explanation

Correct Answer: B

Headless compression screws are particularly advantageous in articular and periarticular fractures (like the scaphoid) because their design allows them to be completely buried beneath the cartilage or cortical surface. This eliminates prominence of the screw head, preventing soft tissue irritation, damage to articular cartilage, and making them suitable for intra-articular placement. They also provide compression across the fracture line due to differential pitch (distal threads have a coarser pitch than proximal threads, pulling the fragments together).

Question 41

A 45-year-old male sustains a transverse midshaft femur fracture. The surgeon performs antegrade intramedullary nailing using a piriformis fossa entry portal. If the entry point is placed too far medially in the piriformis fossa, what is the most likely biomechanical consequence?





Explanation

Correct Answer: C

The piriformis fossa entry portal is a common approach for antegrade femoral nailing. Proper placement is crucial to avoid malalignment. If the entry point is too far medially in the piriformis fossa, the intramedullary nail will be forced to enter the canal in a more medial position relative to the mechanical axis of the femur. As the nail is advanced, it will tend to push the proximal femoral fragment into a varus position, leading to varus malalignment. Conversely, an entry point that is too lateral (e.g., through the greater trochanter tip or a more lateral piriformis entry) can lead to valgus malalignment. While sciatic nerve injury (Option D) is a potential complication of piriformis fossa entry, it is not the most likely biomechanical consequence of a medial entry point in terms of fracture alignment. Difficulty with distal interlocking (Option E) is more often related to rotational malalignment or technical issues, not primarily the medial entry point itself causing varus.

Question 42

A 60-year-old female sustains a transverse olecranon fracture after a fall. She is treated with tension band wiring. What is the primary biomechanical principle that makes tension band wiring an effective fixation method for this type of fracture?





Explanation

Correct Answer: B

Tension band wiring is a powerful biomechanical technique used for fractures subjected to eccentric tensile forces (e.g., olecranon, patella, medial malleolus). The primary principle is to convert these tensile forces, which would otherwise cause distraction at the fracture site, into compressive forces. This is achieved by placing a wire (the tension band) on the tension side (e.g., posterior aspect of the olecranon, anterior aspect of the patella) and anchoring it to the bone on the opposite side. When the muscle (e.g., triceps for olecranon) contracts, it applies a tensile force to the fragment. The tension band resists this pull, and because the fracture is on the compression side (e.g., articular surface of the olecranon), the tensile force in the wire is converted into compression across the fracture site, promoting healing and stability. It does not provide absolute rigidity (Option A) but rather relative stability with dynamic compression. It is not primarily a buttress (Option C) and does not rely on friction (Option D). It aims for compression, not distraction (Option E).

Question 43

A 75-year-old female with an intertrochanteric hip fracture is treated with a Dynamic Hip Screw (DHS). What is the primary biomechanical advantage of the sliding barrel-plate mechanism of the DHS in this fracture pattern?





Explanation

Correct Answer: B

The Dynamic Hip Screw (DHS) is designed with a lag screw that is inserted into the femoral head and neck, which then slides within a barrel attached to a side plate. This sliding mechanism is the core biomechanical advantage for intertrochanteric fractures. It allows for controlled collapse and impaction of the fracture fragments under physiological loading. This impaction increases the stability of the fracture, promotes secondary bone healing by bringing the fragments into close apposition, and reduces the risk of screw cutout from the osteoporotic femoral head. While the lag screw provides some rotational stability, its primary dynamic function is axial sliding. The DHS is a load-sharing device, not load-bearing (Option C). Its design does not directly impact avascular necrosis risk (Option D) or inherently facilitate minimally invasive techniques (Option E), although some techniques can be less invasive.

Question 44

A 50-year-old male sustains a highly comminuted distal tibia fracture (pilon fracture). He is treated with a bridging locking plate. What is the primary biomechanical principle guiding the surgical technique for this type of fixation to optimize healing?





Explanation

Correct Answer: B

For highly comminuted fractures, especially in metaphyseal or articular regions like pilon fractures, the goal is often 'biological fixation' or 'relative stability' rather than absolute anatomical reduction and compression. Bridging locking plates are ideal for this. The primary biomechanical principle guiding the surgical technique is to minimize soft tissue dissection (e.g., using MIPO techniques) and preserve the periosteal blood supply. This approach prioritizes the biological environment for healing, allowing for callus formation (secondary bone healing) in a relatively stable, yet not rigidly compressed, environment. Attempting absolute anatomical reduction and compression (Option A) in highly comminuted fractures can lead to extensive soft tissue stripping, devascularization of fragments, and impaired healing. Maximizing stiffness (Option C) or using a short working length (Option D) would create a very rigid construct, which can inhibit callus formation and lead to stress shielding. Pre-bending (Option E) is typically for conventional compression plating of simple fractures, not bridging comminuted fractures.

Question 45

A surgeon is fixing an oblique fibula fracture with a lag screw. What is the critical biomechanical purpose of drilling a 'glide hole' (oversized hole) in the near cortex?





Explanation

Correct Answer: D

The lag screw principle is fundamental for achieving interfragmentary compression across oblique or spiral fractures. For a lag screw to function correctly, it must only engage the far cortex (the fragment being pulled) and not the near cortex (the fragment through which the screw passes). The 'glide hole' (also known as the 'oversized hole' or 'near cortex hole') is drilled with a diameter larger than the screw's outer thread diameter. This allows the screw threads to pass freely through the near cortex without engaging it. When the screw is tightened, its head compresses against the near cortex, and the threads engage only the far cortex, pulling the far fragment towards the near fragment and generating interfragmentary compression. Without a glide hole, the screw would engage both cortices, functioning as a position screw and preventing the desired compression.

Question 46

A 30-year-old patient with a simple transverse midshaft femoral fracture is treated with a stainless steel plate. If a titanium plate of identical geometry were used instead, what would be the primary biomechanical difference relevant to bone healing?





Explanation

Correct Answer: C

The primary biomechanical difference between stainless steel and titanium plates of identical geometry, relevant to bone healing, lies in their modulus of elasticity. Titanium and its alloys have a modulus of elasticity closer to that of cortical bone (approximately 110 GPa for titanium vs. 200 GPa for stainless steel vs. 17-20 GPa for cortical bone). A lower modulus of elasticity means the implant is less stiff. When a less stiff implant is used, it shares more load with the bone, allowing more physiological stress to be transmitted to the healing fracture. This reduces the phenomenon of 'stress shielding,' where a very stiff implant carries too much load, leading to disuse osteoporosis in the adjacent bone and potentially delayed healing. While titanium is indeed more corrosion-resistant (Option D) and has excellent biocompatibility, its lower modulus of elasticity is the key biomechanical advantage in terms of load sharing and stress shielding. Fatigue life (Option B) can be complex and depends on many factors, but titanium generally has good fatigue properties. Neither material inherently provides greater stiffness (Option A) or compression (Option E) for the same geometry; rather, it's the relative stiffness to bone that is critical.

Question 47

A 25-year-old male with an open tibia fracture is treated with a unilateral external fixator. Which modification would significantly increase the bending and torsional stiffness of the external fixator construct?





Explanation

Correct Answer: C

The stiffness of an external fixator construct is crucial for fracture stability and healing. Several factors influence this stiffness:

  • Number of pins per fragment: Increasing the number of pins per fragment significantly increases stiffness by distributing the load over more points and enhancing the bone-pin interface.
  • Pin diameter: Larger diameter pins are stiffer and provide better purchase in the bone.
  • Pin spacing: Spreading the pins further apart within each fragment (increasing the 'spread' or 'gauge') increases stiffness.
  • Distance between bone and bar: Decreasing the distance between the bone and the connecting bar (reducing the 'working length' of the pins) increases stiffness.
  • Number of connecting bars: Using two connecting bars (a biplanar or delta frame) provides significantly more stiffness than a single bar.
  • Bar diameter and material: Larger diameter bars and stiffer materials (e.g., carbon fiber vs. aluminum) increase stiffness.

Therefore, increasing the number of pins per fragment (Option C) would directly increase the stiffness. Options A, B, D, and E would all decrease the stiffness of the construct.

Question 48

A 40-year-old male sustains a Schatzker Type II tibial plateau fracture with a depressed lateral condyle fragment. After elevation of the depressed articular fragment, a plate is applied to the lateral aspect of the tibia. What is the primary biomechanical function of this plate in this specific scenario?





Explanation

Correct Answer: C

In a Schatzker Type II tibial plateau fracture, the lateral condyle is split and depressed. After surgical elevation of the depressed articular fragment to restore the joint surface, the bone underneath is often deficient or weakened. A buttress plate is applied to the lateral aspect of the tibia to mechanically support the elevated fragment and prevent its re-collapse under axial load. Its primary role is to provide structural support against compressive forces that would otherwise cause the articular surface to sink again. While some screws may provide compression or neutralization, the overarching function of the plate in this context is to act as a buttress. Bridging (Option D) is for comminuted diaphyseal or metaphyseal fractures without direct articular involvement, and controlled micromotion (Option E) is typically for secondary healing in diaphyseal fractures, not for maintaining articular reduction.

Question 49

A surgeon is fixing a fracture in osteoporotic bone using conventional (non-locking) screws. Which factor is most critical in maximizing the pullout strength of these screws in this challenging bone quality?





Explanation

Correct Answer: D

In osteoporotic bone, screw purchase and pullout strength are significantly compromised. While all the listed factors can influence screw strength to some degree, maximizing the number of cortices engaged by the screw is the most critical factor for conventional (non-locking) screws. Engaging two cortices (bicortical purchase) provides significantly greater pullout resistance than engaging only one (monocortical purchase) because it effectively doubles the amount of bone-screw interface and creates a more stable construct. While a larger core diameter (Option A) can increase strength, and a finer thread pitch (Option B) and increased thread depth (Option C) are features of cortical screws designed for dense bone, the overall engagement with multiple cortical layers provides the most substantial increase in pullout strength, especially in poor bone quality. Self-tapping design (Option E) facilitates insertion but does not inherently increase pullout strength compared to pre-drilled screws.

Question 50

A 30-year-old male sustains a long spiral midshaft tibia fracture. He is treated with a reamed, statically locked intramedullary nail. What is the primary mechanism by which the interlocking screws provide rotational stability in this construct?





Explanation

Correct Answer: C

In a statically locked intramedullary nail, the interlocking screws (both proximal and distal) serve two primary biomechanical functions: preventing axial shortening/lengthening and preventing rotation. For a long spiral fracture, the fracture pattern itself offers very little inherent rotational stability. While reaming and a tight fit between the nail and the endosteal surface (Option A) contribute to some rotational stability, it is often insufficient for unstable fracture patterns like long spirals. The interlocking screws pass through holes in the nail and engage the bone cortices, effectively 'locking' the nail to the bone fragments. This direct mechanical interlock prevents relative rotation between the nail and each bone fragment, thereby providing crucial rotational stability to the overall construct. Preventing axial shortening (Option B) is also a function of static locking, but rotational stability is particularly critical for spiral fractures. Increasing bending stiffness (Option D) is primarily a function of nail diameter and material, not the screws themselves. Converting forces (Option E) describes tension band principles, not IM nailing.

Question 51

A 45-year-old female sustains a comminuted distal femur fracture treated with a locking plate. To DECREASE construct stiffness and promote secondary bone healing via callus formation, which modification is most appropriate?





Explanation

Increasing the working length of a plate (the distance between the two closest screws on either side of the fracture) decreases the overall stiffness of the construct. This allows for relative stability and micromotion, which promotes secondary bone healing.

Question 52

A 30-year-old male with an open tibia fracture is managed with a uniplanar external fixator. Which structural modification most significantly increases the bending stiffness of this construct?





Explanation

Bending stiffness of an external fixator is most significantly improved by placing pins closer to the fracture site, moving the connecting rod closer to the bone, and increasing pin diameter. Decreasing the pin-to-fracture distance minimizes the unsupported bone segment.

Question 53

A 55-year-old male undergoes fixation of a short oblique tibial shaft fracture with a single lag screw and a neutralization plate. According to Perren's strain theory, this specific construct requires what level of strain at the fracture gap for successful healing?





Explanation

A lag screw and neutralization plate provide absolute stability, which relies on primary bone healing. Primary bone healing requires the strain at the fracture site to be less than 2% to allow osteoclasts and osteoblasts to cross the gap without disrupting the Haversian systems.

Question 54

A surgeon uses a fully threaded cortical screw as a lag screw to fix a lateral malleolus fracture by overdrilling the near cortex. The pullout strength of this screw is biomechanically most dependent on which of the following variables?





Explanation

Pullout strength is directly proportional to the square of the outer thread diameter, the length of thread engagement, and the shear strength of the bone material. Increasing the outer thread diameter has the most profound effect on pullout resistance.

Question 55

A 22-year-old male with a transverse midshaft humerus fracture is treated with a narrow dynamic compression plate (DCP). The plate is placed on the lateral aspect of the humerus. Which biomechanical principle explains the plate's ability to resist bending forces effectively in this position?





Explanation

Placing a plate on the tension side of a bone converts tensile forces into compressive forces at the fracture site, utilizing the tension band principle. The lateral aspect of the humerus and femur are classic tension sides during physiological loading.

Question 56

During a femoral nailing, a surgeon elects to use a 12 mm solid intramedullary nail instead of a 10 mm solid nail of the exact same material. The torsional rigidity of the 12 mm nail is increased by approximately what factor compared to the 10 mm nail?





Explanation

The torsional rigidity of a solid cylinder is proportional to its polar moment of inertia, which scales with the radius to the fourth power (r^4). Calculating (6^4 / 5^4) yields 1296 / 625, which is an increase by a factor of approximately 2.07.

Question 57

A comminuted subtrochanteric femur fracture is treated with a bridging locked plate. Compared to Stainless Steel (316L), Titanium alloy (Ti-6Al-4V) is often preferred for bridge plating to promote callus formation because it possesses which material property?





Explanation

Titanium alloy has a significantly lower modulus of elasticity (closer to cortical bone) than stainless steel, making it more flexible. This decreased rigidity allows for more interfragmentary motion under load, which promotes secondary bone healing (callus formation).

Question 58

A 25-year-old male sustains a highly comminuted tibia fracture from a high-speed motorcycle crash. Bone fractures with significantly more comminution at high loading rates compared to low-speed falls due to which biomechanical property of bone?





Explanation

Bone is a viscoelastic material, meaning its mechanical properties change based on the rate of loading. At higher strain rates, bone becomes stiffer, absorbs more energy before failure, and ultimately releases that energy explosively, causing high comminution.

Question 59

A distal radius fracture is stabilized with a volar locking plate. Compared to conventional non-locking plates, the stability of this locked construct relies primarily on which biomechanical mechanism?





Explanation

Locked plates function as single-beam constructs where stability depends on the fixed-angle threaded coupling between the screw head and the plate hole. Unlike conventional plates, they do not rely on friction between the plate and the bone.

Question 60

A hypertrophic nonunion of a tibial shaft fracture, initially treated with a statically locked intramedullary nail, undergoes dynamization. Removing the interlocking screws furthest from the fracture promotes healing by allowing what primary biomechanical change?





Explanation

Dynamization involves removing the static locking screws to allow the bone ends to slide along the nail and compress under physiological loads. This increased axial micromotion stimulates secondary bone healing in a hypertrophic nonunion.

Question 61

A surgeon aims to increase the bending stiffness of a conventional compression plate used for a diaphyseal fracture. Biomechanically, the bending stiffness of the plate is proportional to its thickness raised to what power?





Explanation

The bending stiffness of a plate with a rectangular cross-section depends on its area moment of inertia, calculated as (base * height^3) / 12. Therefore, bending stiffness is proportional to the thickness (height) cubed.

Question 62

Bilateral femur fractures are treated with an 11 mm solid nail on the right and an 11 mm cannulated nail (inner diameter 5 mm) on the left. Assuming identical materials, how does the bending rigidity of the solid nail compare to the hollow nail?





Explanation

The area moment of inertia for a hollow cylinder subtracts the inner radius to the fourth power. Because the inner radius is small (2.5 mm) compared to the outer (5.5 mm), the inner core contributes very little to overall rigidity, making the difference less than 5%.

Question 63

A 3-part proximal humerus fracture is treated with a locking plate. Using 'far cortical locking' (FCL) screws provides what specific biomechanical advantage over standard locking screws in a bridge plating construct?





Explanation

FCL screws have a reduced-diameter shaft that bypasses the near cortex and locks only into the plate and far cortex. This allows the plate to act as a flexible cantilever, providing parallel, symmetric interfragmentary micromotion to stimulate robust callus formation.

Question 64

A transverse olecranon fracture is treated with tension band wiring. For this construct to successfully function as a dynamic tension band, which mechanical condition is absolutely required during active elbow flexion?





Explanation

A tension band converts tensile forces on the convex surface into compressive forces at the fracture site. For this to work without construct failure, the opposite cortex (the articular/concave side) must be intact to buttress and withstand these compressive forces.

Question 65

During open reduction of a clavicle fracture, the surgeon extensively bends a reconstruction plate back and forth to match the bone's S-shape. This repetitive plastic deformation increases the risk of implant failure primarily by inducing which material phenomenon?





Explanation

Repeated bending of a metal plate beyond its yield point causes cold working (strain hardening), which increases the metal's brittleness and decreases its fatigue life. This makes the implant highly susceptible to early fatigue failure before the fracture heals.

Question 66

A patient undergoes ORIF of a bimalleolar ankle fracture. A stainless steel plate is applied to the fibula, but titanium screws are mistakenly used to secure it. This mixing of dissimilar metals places the construct at highest risk for which complication?





Explanation

Galvanic corrosion occurs when two dissimilar metals with different anodic indices are placed in electrical contact within an electrolytic environment (like body fluid). This accelerates corrosion of the less noble metal, potentially leading to implant failure or localized tissue toxicity.

Question 67

A comminuted midshaft femur fracture is treated with a bridge plate. To maximize the fatigue life of the plate and prevent early breakage, which surgical strategy regarding screw placement is most effective?





Explanation

Leaving screw holes empty over the fracture zone increases the working length of the plate. A longer working length distributes bending stresses over a larger segment of the plate, significantly reducing the strain per unit area and thereby increasing the implant's fatigue life.

Question 68

A surgeon uses a single lag screw to stabilize an oblique tibial shaft fracture. To achieve the maximal amount of interfragmentary compression, what must be the orientation of the lag screw relative to the fracture anatomy?





Explanation

To maximize interfragmentary compression and prevent shear forces that could cause fracture displacement (gliding), a lag screw must be placed perfectly perpendicular to the fracture plane.

Question 69

A supra-acetabular external fixator is placed for a pelvic ring injury. To optimally decrease the stresses at the pin-bone interface and minimize the risk of pin loosening, which biomechanical adjustment is best?





Explanation

Pin loosening is primarily caused by excessive stress at the pin-bone interface. Increasing the diameter of the Schanz pins exponentially increases their bending stiffness (proportional to r^4), drastically reducing micromotion and stress at the bone interface.

Question 70

A retrieved broken femoral plate from a nonunion is subjected to mechanical testing. Analysis shows the plate failed due to repetitive sub-maximal loading at stress levels well below its ultimate tensile strength. This failure mode is defined as:





Explanation

Fatigue failure occurs when a material undergoes repetitive cyclic loading at stress levels below its yield point or ultimate tensile strength, eventually leading to microscopic crack propagation and macroscopic failure. It is a common cause of implant failure in nonunions.

Question 71

Increasing the thickness of a fracture plate has what mathematical effect on its bending stiffness?





Explanation

The bending stiffness of a rectangular plate is proportional to its area moment of inertia, calculated as (base x height^3) / 12. Therefore, increasing the thickness (height) increases the stiffness by the cube of that change.

Question 72

Which of the following modifications to a cortical screw will most significantly increase its resistance to bending forces (bending stiffness)?





Explanation

The bending stiffness of a screw is proportional to the radius of its core (inner) diameter to the fourth power. Therefore, increasing the core diameter drastically increases its bending strength and resistance to fatigue failure.

Question 73

A surgeon is applying a unilateral external fixator to a tibial shaft fracture. Which of the following modifications will most effectively increase the bending stiffness of the construct?





Explanation

External fixator stiffness is highly dependent on pin diameter, as stiffness is proportional to the radius to the fourth power (r^4). Increasing the pin diameter is the single most effective way to increase the overall stiffness of the construct.

Question 74

According to Perren's strain theory, what is the maximum allowable interfragmentary tissue strain for primary bone healing to occur via cutting cones?





Explanation

Primary bone healing (osteonal reconstruction via cutting cones) requires absolute stability with an interfragmentary gap strain of less than 2%. Strains between 2% and 10% promote secondary bone healing via callus formation.

Question 75

In a locked plating construct, how is the stability of the fracture primarily achieved compared to conventional plating?





Explanation

Locked plates act as fixed-angle constructs where the screws thread directly into the plate, functioning as a single load-bearing beam. Unlike conventional plates, they do not rely on friction between the plate and bone for stability.

Question 76

Cortical bone is a viscoelastic material. How does its biomechanical behavior change when it is loaded at a very high rate, such as during high-energy trauma?





Explanation

As a viscoelastic material, cortical bone becomes stiffer and stronger when loaded rapidly. This allows it to absorb more energy before fracturing during high-velocity impacts, which typically leads to more comminuted fracture patterns upon failure.

Question 77

For a tension band construct of the patella to function properly, where must the wire be placed relative to the joint line and the bending axis?





Explanation

The tension band principle relies on placing the implant on the tension side of a bone (anterior patella). This converts the tensile forces generated during knee flexion into dynamic compressive forces at the articular surface.

Question 78

A surgeon uses a bridging plate for a highly comminuted diaphyseal fracture. Leaving empty screw holes over the fracture site increases the construct's "working length". What is the primary biomechanical effect of this technique?





Explanation

Increasing the working length of a plate (the distance between the two innermost screws) decreases the bending stiffness of the construct. This relative flexibility lowers stress concentrations at any single point and promotes secondary bone healing via callus formation.

Question 79

When placing a cortical lag screw across an oblique fracture, the gliding hole in the near cortex must be overdrilled. What biomechanical consequence occurs if the near cortex is not overdrilled?





Explanation

If the near cortex is not overdrilled to create a gliding hole, the screw threads engage both cortices simultaneously. This locks the fragments at their current distance and prevents interfragmentary compression.

Question 80

A manufacturer redesigns an intramedullary nail by replacing its open, slotted cross-section with a closed, solid tubular cross-section of the same outer diameter. What is the most significant biomechanical change?





Explanation

A closed-section intramedullary nail has dramatically higher torsional rigidity compared to an open (slotted) nail. Slotted nails are more flexible in torsion, which can lead to malrotation if the fracture is not adequately locked.

Question 81

In the context of intramedullary nailing, how is the "working length" of the nail construct defined?





Explanation

The working length of an IM nail is the distance between the two closest points of firm fixation (or locking screws) immediately proximal and distal to the fracture site. Decreasing this working length increases the stiffness of the nail construct.

Question 82

The pullout strength of a bone screw is directly proportional to all of the following EXCEPT:





Explanation

Pullout strength is determined by the outer thread diameter, length of engagement, thread factor, and bone shear strength. The inner core diameter primarily determines the screw's bending stiffness and fatigue resistance, not its pullout strength.

Question 83

A surgeon exchanges a 10 mm intramedullary nail for a 12 mm intramedullary nail of the same material. Assuming a solid cylindrical design, by approximately what factor does the bending stiffness increase?





Explanation

The bending stiffness of a solid cylinder is proportional to the radius to the fourth power (r^4). Increasing the radius from 5 mm to 6 mm increases the stiffness by a factor of (6/5)^4, which is approximately 2.07 times.

Question 84

In external fixation, increasing the distance between the near and far pins within a single bone fragment (pin spread) has what biomechanical effect on the construct?





Explanation

Increasing the distance between the pins within a single fragment maximizes the mechanical advantage of the frame. This distributes the load more effectively, thereby increasing the overall stability and stiffness of the external fixator construct.

Question 85

A 45-year-old patient undergoes ORIF using a stainless steel plate and titanium screws. What specific biomechanical or biomaterial complication is most likely to occur at the screw-plate interface over time?





Explanation

Galvanic corrosion occurs when two dissimilar metals (such as titanium and stainless steel) are placed in direct physical contact within an electrolytic environment like body fluids. This electrochemical reaction leads to the rapid corrosion of the less noble metal.

Question 86

A rigid, thick plate is applied to the anterior femur. Years later, dual-energy x-ray absorptiometry reveals severe osteopenia of the underlying anterior femoral cortex. What biomechanical principle explains this phenomenon?





Explanation

Stress shielding occurs when a highly rigid implant offloads the normal physiological stresses from the underlying bone. According to Wolff's law, bone remodels in response to mechanical stress; therefore, the lack of stress leads to localized osteopenia.

Question 87

Cortical screws typically have a smaller pitch compared to cancellous screws. What does the term "pitch" refer to in screw biomechanics?





Explanation

Screw pitch is defined as the linear distance traveled by the screw with one full 360-degree turn, which corresponds to the distance between adjacent threads. Cancellous screws have a larger pitch to capture more bone per turn in less dense trabecular bone.

Question 88

When applying a titanium locking plate in a bridge plating technique for a comminuted fracture, what is the biomechanical consequence of placing screws in the holes immediately adjacent to the fracture gap?





Explanation

Placing screws immediately adjacent to the fracture site significantly decreases the plate's working length. In a bridging construct, this makes the segment too rigid, concentrating stress over a small area and increasing the risk of implant fatigue failure or nonunion.

Question 89

Which of the following accurately describes the typical failure mechanism of a locked plating construct under excessive axial load compared to a non-locked construct?





Explanation

Because a locked plate acts as a single fixed-angle beam, the screws do not fail sequentially. Under excessive load, the entire construct typically fails simultaneously, often through catastrophic en masse screw pullout or plate breakage.

Question 90

Cortical bone exhibits different mechanical properties depending on the direction of the applied load. It is strongest in compression and weakest in shear. What is the biomechanical term for this property?





Explanation

Anisotropy refers to a material having different mechanical properties when loaded in different directions. Cortical bone is highly anisotropic, being strongest under longitudinal compression and weakest under transverse shear forces.

Question 91

A 45-year-old male undergoes open reduction and internal fixation of a transverse patella fracture using a tension band construct. For this construct to function optimally and convert tensile forces into compressive forces at the articular surface, where must the tension band be primarily placed?





Explanation

According to tension band principles, the implant must be applied to the tension side of the bone. When the knee flexes, the anterior surface of the patella experiences tensile forces, which the tension band wire converts to compression at the articular side.

Question 92

A surgeon is evaluating screw options for osteoporotic bone fixation. According to the biomechanical equation for screw pull-out strength, which of the following modifications will most significantly increase the holding power of a cortical screw?





Explanation

Screw pullout strength is most significantly determined by the outer thread diameter. Pullout strength is directly proportional to the outer diameter, thread engagement length, and shear strength of the bone, and inversely proportional to thread pitch.

Question 93

According to Perren's strain theory, what range of interfragmentary strain is optimally tolerated by a fracture gap to promote secondary bone healing (callus formation) without progressing to primary healing or nonunion?





Explanation

Perren's strain theory dictates that absolute stability (strain <2%) results in primary bone healing without callus. Strain between 2% and 10% promotes secondary bone healing via callus formation, while strain >10% typically leads to fibrous tissue and nonunion.

Question 94

A 65-year-old female sustains a comminuted distal femur fracture treated with a lateral locking plate. The surgeon intentionally leaves three empty screw holes directly over the fracture site. What is the primary biomechanical effect of this technique?





Explanation

Increasing the working length (the distance between the two closest screws across a fracture) decreases the construct's bending stiffness, allowing for more flexible fixation. This controlled micro-motion stimulates secondary bone healing via callus formation.

Question 95

An orthopedic resident is applying a bridging unilateral external fixator for a highly comminuted tibial plateau fracture. Which of the following technical modifications will most effectively increase the overall bending stiffness of this construct?





Explanation

Increasing the pin spread (the distance between the innermost and outermost pins within the same bone fragment) significantly increases the stiffness of an external fixator. Moving the bar closer to the bone and increasing pin diameter are other effective ways to increase stiffness.

Question 96

A surgeon decides to use a titanium intramedullary nail instead of a stainless steel nail for a tibial shaft fracture. Which of the following accurately describes a key biomechanical difference between titanium alloy (Ti-6Al-4V) and 316L stainless steel?





Explanation

Titanium alloy has a lower modulus of elasticity than stainless steel, making it less rigid and closer to the modulus of elasticity of cortical bone. This property significantly reduces stress shielding at the fracture site compared to stiffer stainless steel implants.

Question 97

A surgeon is applying a dynamic compression plate (DCP) for a diaphyseal forearm fracture. When comparing traditional non-locking plate constructs to fixed-angle locking constructs, what is the primary mode of failure for a non-locking construct subjected to excessive bending loads?





Explanation

Traditional non-locking constructs rely on friction between the plate and bone for stability and primarily fail sequentially via screw pullout (toggle) when overloaded. In contrast, locking constructs function as single fixed-angle devices and typically fail by simultaneous screw fracture or bone failure.

Question 98

During the fixation of a spiral fibula fracture, a lag screw is inserted perpendicular to the fracture plane. If the surgeon mistakenly drills the near cortex with a drill bit matching the core diameter of the screw instead of the outer thread diameter, what is the expected biomechanical consequence?





Explanation

For a lag screw to effectively compress two fragments, it must glide freely through the near cortex (gliding hole) and only engage the far cortex. If the near cortex is drilled to the core diameter, the threads will engage both cortices simultaneously, preventing interfragmentary compression.

Question 99

An intramedullary nail is selected for a subtrochanteric femur fracture. Biomechanically, the torsional rigidity of a solid cylindrical intramedullary nail is proportional to the nail's radius raised to which power?





Explanation

The torsional rigidity and bending stiffness of a solid cylinder are proportional to its polar area moment of inertia, which is dictated by the radius to the fourth power (r^4). Therefore, even a small increase in nail diameter profoundly increases its mechanical rigidity.

Question 100

A diaphyseal tibial fracture is stabilized with a statically locked intramedullary nail. Which of the following best defines the "working length" of this specific intramedullary nail construct?





Explanation

The working length of a statically locked intramedullary nail is defined as the unsupported span between the closest proximal and distal points of fixation (the innermost locking screws). Decreasing the working length increases the stiffness of the nail construct.

None

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